Phân tích đa thức thành nhân tử???

T

tranvanhung7997

$16x^8 + y^8 = (4x^4)^2 + 2.4x^4.y^4 + y^8 - 8x^4y^4$

$= (4x^4 + y^4)^2 - (2\sqrt[]{2}x^2y^2)^2$

$= (4x^4 + y^4 + 2\sqrt[]{2}x^2y^2)(4x^4 + y^4 - 2\sqrt[]{2}x^2y^2)$
 
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