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eunhyuk_0330

2a5+4a4−7a3+5a2−17a+52a^5+4a^4-7a^3+5a^2-17a+5
=2a5+3a3−a2+4a4+6a2−2a−10a3−15a+5=2a^5+3a^3-a^2+4a^4+6a^2-2a-10a^3-15a+5
=a2(2a3+3a−1)+2a(2a3+3a−1)−5(2a3+3a−1)=a^2(2a^3+3a-1)+2a(2a^3+3a-1)-5(2a^3+3a-1)
=(2a3+3a−1)(a2+2a−5)=(2a^3+3a-1)(a^2+2a-5)
 
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0973573959thuy

Chúc bạn học tốt!

2a5+4a4−7a3+5a2−17a+52a^5 + 4a^4 - 7a^3 + 5a^2 - 17a + 5

=2a5+4a4−10a3+3a3+6a2−a2−15x−2x+5= 2a^5 + 4a^4 - 10a^3 + 3a^3 + 6a^2 - a^2 - 15x - 2x + 5

=(2a5+3a3−a2)+(4a4+6a2−2a)−(10x3+15x−5)= (2a^5 + 3a^3 - a^2) + (4a^4 + 6a^2 - 2a) - (10x^3 + 15x - 5)

=a2(2a3+3a−1)+2a(2a3+3a−1)−5(2a3+3a−1)= a^2(2a^3 + 3a - 1) + 2a(2a^3 + 3a - 1) - 5( 2a^3 + 3a - 1)

=(a2+2a−5)(2a3+3a−1)= (a^2 + 2a - 5)(2a^3 + 3a - 1)
 
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