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Cho A= $\dfrac{(2^{3}+1)(3^{3}+1)(4^{3}+1)...(10^{3}+1)}{(2^{3}-1)(3^{3}-1)(4^{3}-1)...(10^{3}-1)}$
So sánh A...$\dfrac{3}{2}$
So sánh A...$\dfrac{3}{2}$
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