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iceghost

$a)\dfrac{11x+13}{3x-3}-\dfrac{15x+17}{4x-4} \\
= \dfrac{11x+13}{3(x-1)}-\dfrac{15x+17}{4(x-1)} \\
= \dfrac{4(11x+13)}{12(x-1)}-\dfrac{3(15x+17)}{12(x-1)} \\
= \dfrac{4(11x+13)-3(15x+17)}{12(x-1)} \\
= \dfrac{44x+52-45x-51}{12(x-1)} \\
= \dfrac{-x+1}{12(x-1)} \\
= \dfrac{-(x-1)}{12(x-1)} \\
= \dfrac{-1}{12}$
 
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