niuton!

N

nguyenbahiep1

[TEX] ( 1+ 2x)^n = C_n^0.1^{n} + C_n^1.1^{(n-1)}.2.x + C_n^0.1^{n-2}.2^2.x^2+ ......+ C_n^n.2^n.x^n[/TEX]

[TEX]\Rightarrow a_0 = C_n^0.1 \\ a_2 = C_n^1.1^{n-1}.2 \\ ............................. .\\ a_n = C_n^n.2^n \\ A = a_0 + \frac{a_1}{2}+....+\frac{a_n}{2^n} = C_n^0+C_n^1+...+C_n^n = (1+1)^n = 4096 \Rightarrow n = 12[/TEX]
 
Top Bottom