1. Chứng minh nếu abc = 1 thì:
a/(ab+a+1) + b/(bc+b+1) + c/(ca+c+1) = 1
CAU NJ LAM DAI NEK

[TEX]\frac{a}{ab+a+1}+\frac{b}{bc+b+1}+\frac{c}{ca+c+1}[/TEX]
[TEX]=\frac{a}{ab+a+abc}+\frac{b}{bc+b+1}+\frac{c}{ca+c+1} [/TEX]
[TEX]=\frac{a}{a(bc+b+1)}+\frac{b}{bc+b+1}+\frac{c}{ca+c+1} [/TEX]
[TEX]=\frac{a+ab}{a(bc+b+1)}+\frac{c}{ca+c+1} [/TEX]
[TEX]=\frac{a+ab}{ab(ca+c+1)}+\frac{c}{ca+c+1}[/TEX]
[TEX]=\frac{a+ab +abc}{ab(ca+c+1)}[/TEX]
[TEX]=\frac{a(1+b+bc)}{abc(a+ab+1)}[/TEX]
[TEX]=\frac{a(1+b+bc)}{a+ab+1}[/TEX]
[TEX]=\frac{a(1+b+bc)}{a(1+b+bc)}[/TEX]
[TEX]=1[/TEX](dpcm)