nhờ giải dùm 1 bài nguyên hàm đơn giản

J

jumiko

[TEX]I=\int_{}^{}\frac{dx}{x(x+1)}=\int_{}^{}(\frac{1}{x}-\frac{1}{x+1})dx=\int_{}^{}\frac{1}{x}dx-\int_{}^{}\frac{1}{x+1}dx=ln(x)-ln(x+1)[/TEX]
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