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steelheart1809


(1)\Leftrightarrow $2x^2-11x+15=3\sqrt[3]{4x-4}-6$
\Leftrightarrow $(x-3)(2x-5)=3[\frac{{\sqrt[3]{4x-4}^3-2^3}}{\sqrt[3]{(4x-4)^2}+2\sqrt[3]{4x-4}+4}]$
\Leftrightarrow $(x-3)(2x-5)=12\frac{x-3}{\sqrt[3]{(4x-4)^2}+2\sqrt[3]{4x-4}+4}$
Hai ve co cung nhan tu x-3\Rightarrow nhom lai va phan sau danh cho ban.
Cau (2) tuong tu
Neu dung xac nhan giup minh nhe
 
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