có [tex]f(x)+3f(\frac{1}{x})=x^2\Rightarrow \left\{\begin{matrix} f(2)+3f(\frac{1}{2})=2^2=4\\ f(\frac{1}{2})+3f(2)=\frac{1}{4} \end{matrix}\right. \Rightarrow \left\{\begin{matrix} f(2)+3f(\frac{1}{2})=4\\ 3f(\frac{1}{2})+9f(2)=\frac{3}{4} \end{matrix}\right.[/tex]
Trừ vế với vế ta được [tex]-8f(2)=\frac{13}{4}\Rightarrow f(2)=\frac{-13}{32}[/tex]