a, [tex]2x^{2}+5x+3=0<=>2x^{2}+2x+3x+3=0<=>2x(x+1)+3(x+1)=0<=>(2x+3)(x+1)=0=>..[/tex]
b, tương tự
c, [tex]x^{2}+7x+10=0<=>x^{2}+2x+5x+10=0<=>x(x+2)+5(x+2)=0<=>(x+5)(x+2)=0=>...[/tex]
Mình làm a, các phần sau tương tự
a,[tex]2x^2+5x+3=0\\\Leftrightarrow 2(x^2+\frac{5}{2}x+\frac{3}{2})=0\\\Leftrightarrow 2(x^2+\frac{5}{2}x+\frac{25}{16}-\frac{1}{16})=0\\\Leftrightarrow 2(x+\frac{5}{2})^2=\frac{1}{8}\\\Leftrightarrow (x+\frac{5}{2})^2=\frac{1}{4}=(\frac{1}{2})^2\\\Leftrightarrow ...[/tex]