[tex]sin(\frac{\pi }{2}+2x)+\sqrt{3}sin(\pi -2x)=1[/tex]
=>[tex]\frac{1}{2}.sin(\frac{\pi }{2}+2x)+\frac{\sqrt{3}}{2}.sin(\pi -2x)=sin\frac{\pi }{6}.cos2x+cos\frac{\pi }{6}.sin2x=sin(2x+\frac{\pi }{6})=\frac{1}{2}=sin\frac{\pi }{6}[/tex] =>Tự giải nốt nhé!