a) Ta có:[tex]\frac{1}{AH^2}=\frac{1}{AB^2}+\frac{1}{AC^2}\Rightarrow AH=...[/tex]
b)Dễ chứng minh [tex]\Delta AMN\sim \Delta ACB\rightarrow \frac{S_{AMN}}{S_{ABC}}=(\frac{MN}{BC})^2=(\frac{AH}{BC})^2\Rightarrow \frac{S_{MNCB}}{S_{ABC}}=1-(\frac{AH}{BC})^2\Rightarrow S_{MNCB}=...[/tex]