mọi người giúp em vs ạ

T

thucle.1998@gmail.com

)goi M la trung diem canh BC
vi qB=qC ma BM=CM nen dien truong cua qB,qC tai M nguoc chieu
cung do lon=>
vay dien truong tai M la tu truong do qA gay ra
E=k.qA/(AM^2)
ma tam giac ABC deu=>AM=AB.can3 /2
=>E=12000V/m
chieu tu A=>M
1nC=10^-9C
 
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