mn giải dùm mik nhé, mai kt rồi á

K

kelvinhai

$v = 2\ m/s$; $v_0 = 0\ m/s$; $a = 0,1\ m/s^2$

$v=v_0.t + \frac{1}{2}.a.t^2$ \Rightarrow $2 = 0,1.t^2$ \Leftrightarrow $t^2 = 20$ \Leftrightarrow ...................
 
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