Mấy bài kho khó toán 8 nè

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ongninja

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luongxuanphong

[TEX](x+1)(x+2)(x+3)(x+4) = (x^2+ 5x+4)(x^2 +5x+6)[/TEX] (*)
[TEX]dat x^2+5x+5=t \geq -1,25[/TEX]
[TEX](t-1)(t+1)=40// t^2-1=40[/TEX]
[TEX]\Rightarrow t^2=41 \Rightarrow t=+-\sqrt{41}[/TEX]
[TEX]\Rightarrow x^2+5x+5=+-\sqrt{41}[/TEX]
[TEX]\Rightarrow x=???[/TEX]
 
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