[lý 10]- tính bán kính

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huuvunguyen

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nguyenquynang98

Theo đề bài [TEX] a_{ht}=10g=98 (m/s^2) \Leftrightarrow \frac{v^2}{r}=98 \Leftrightarrow r=\frac{v^2}{98} \Leftrightarrow r=\frac{(\frac{2000}{9})^2}{98}=503,9 [/TEX]
 
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