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hetientieu_nguoiyeucungban
![](https://blog.hocmai.vn/wp-content/uploads/2017/07/hot.gif)
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[TEX]1)4\sqrt{2}sin^{3}x-4cos^{3}x+\sqrt{2}sin(x+\frac{\pi }{4})-2cos(x-\frac{\pi }{4})=0[/TEX]
[TEX]2)sin^{10}x+cos^{10}x=\frac{29}{16}cos^{4}2x[/TEX]
[TEX]3)\frac{sin^{2}x+cos^{4}2x}{\sqrt{sinx.cosx}}=0[/TEX]
[TEX]2)sin^{10}x+cos^{10}x=\frac{29}{16}cos^{4}2x[/TEX]
[TEX]3)\frac{sin^{2}x+cos^{4}2x}{\sqrt{sinx.cosx}}=0[/TEX]