Cos^2 - căn3 sin2x = 1 + sin^2x
( e ko biết ghi căn nên mn thông cảm )
[tex]pt\Leftrightarrow \frac{1+cos2x}{2}-\sqrt{3}sin2x=1+\frac{1-cos2x}{2}\Leftrightarrow cos2x-\sqrt{3}sin2x=1\Leftrightarrow cos\left ( 2x+\frac{\pi }{3} \right )=\frac{1}{2}[/tex]