K
kimtram96


giải giúp mình bài này:
1) [ [TEX]sin^3[/TEX](x/2) + [TEX]cos^3[/TEX] (x/2) ] / (2+sinx)=1/3 cosx
2) 2sin2x - cos2x = 7sinx + 2cosx - 4
1) [ [TEX]sin^3[/TEX](x/2) + [TEX]cos^3[/TEX] (x/2) ] / (2+sinx)=1/3 cosx
2) 2sin2x - cos2x = 7sinx + 2cosx - 4
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