lượng giác!

P

phuonghanh_09

[TEX]9cos^{12}x - 6cos^6xcos2x + cos^2 2x - 2(3cos^6x - cos2x) + 1 = 0[/TEX]
\Leftrightarrow [TEX]( 3cos^6x - cos2x)^2 - 2(3cos^6x - cos2x) + 1 = 0[/TEX]
\Leftrightarrow[TEX] (3cos^6x - cos2x- 1)^2 = 0[/TEX]
\Leftrightarrow [TEX]3cos^6x - cos2x- 1 = 0[/TEX]
đến đây thì dễ rùi.hi
 
Last edited by a moderator:
Top Bottom