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[TEX]\frac{sinx+sin3x+sin5x}{cosx+cos3x+cos5x}=\frac{2sin3xcos2x+sin3x}{2cos3xcos2x+cos3x}=\frac{sin3x(2cos2x+1)}{cos3x(2cos2x+1)}=tan3x(dpcm)[/TEX]
 
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