M
mikochan_311


\[
c{\rm osx + }\sqrt {\rm 3} {\rm sinx = }\frac{{\rm 3}}{{c{\rm osx + }\sqrt {{\rm 3 }} {\rm sinx + 1}}}
\]
c{\rm osx + }\sqrt {\rm 3} {\rm sinx = }\frac{{\rm 3}}{{c{\rm osx + }\sqrt {{\rm 3 }} {\rm sinx + 1}}}
\]
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