Lượng giác 10

K

kingofall96

Đúng thì thank nha bạn

cos3A+cos3B+cos3C=[TEX]2cos(\frac{3(A+B)}{2}) cos(\frac{3(A-B)}{2})+1-2sin^2\frac{3C}{2}[/TEX]
[TEX]=1-2sin(\frac{3C}{2})cos(\frac{3(A-B)}{2})-2sin(\frac{3C}{2})cos(\frac{3(A+B)}{2})[/TEX]
[TEX]=1-2sin(\frac{3C}{2})(cos(\frac{3(A-B)}{2})-cos(\frac{3(A+B)}{2}))[/TEX]
[TEX]=1-4sin(\frac{3A}{2}) sin(\frac{3B}{2}) sin(\frac{3C}{2})[/TEX]
 
K

kaitokid_96

Hình như bạn nhầm dấu chỗ :
[/TEX]-2sin(\frac{3C}{2})cos(\frac{3(A+B)}{2})[/TEX]
 
Top Bottom