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niemkieuloveahbu

[TEX]DK: cos2x \neq 0 \Leftrightarrow 2x \neq \frac{\pi}{2}+k\pi \Leftrightarrow x \neq \frac{\pi}{4}+\frac{k\pi}{2}, k\in Z[/TEX]

[TEX]PT \Leftrightarrow \frac{sin2x}{cos2x}-sin2x+cos2x-1=0\\ \Leftrightarrow (1-cos2x)sin2x+(cos2x-1)cos2x=0\\ \Leftrightarrow (1-cos2x)(sin2x-cos2x)=0[/TEX]

OK nhé bạn!
 
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