N
noooo
![](https://blog.hocmai.vn/wp-content/uploads/2017/07/hot.gif)
![](https://blog.hocmai.vn/wp-content/uploads/2017/07/hot.gif)
1.\int_{}^{}frac{6x^3+8x+1}{(frac3x^2+4)*sqrt{x^2+1}}
2.\int_{}^{}\sqrt{x^2+2}{x^2-1}dx
3.\int_{}^{}\frac{sinx}{cosx*sqrt{(sinx)^2+1}dx
do danh cong thuc kem nen minh dich tieng VIET ne![Big Grin :D :D](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
1.6nhan voi x^3 +8x+1 chia cho (3x^2+4) nhan voi can bac 2 cua x^2 +1
2.\int_{}^{}cuâcn bac 2 cua (x^2+1) chia cho x^2-1
3.\int_{}^{}cua sin chia cho cosx nhan voi can bac hai cua (sinx ^2+1)?mong cac ban noi phuong phap truoc nha co the ko can giai >> RAT MONG DUOC CAC BAN CHIA SE NHUNG CACH LAM BAI THU VJ ?> THANKIU NHIEU NA!!!!!!!!1:KHI(69):
2.\int_{}^{}\sqrt{x^2+2}{x^2-1}dx
3.\int_{}^{}\frac{sinx}{cosx*sqrt{(sinx)^2+1}dx
do danh cong thuc kem nen minh dich tieng VIET ne
1.6nhan voi x^3 +8x+1 chia cho (3x^2+4) nhan voi can bac 2 cua x^2 +1
2.\int_{}^{}cuâcn bac 2 cua (x^2+1) chia cho x^2-1
3.\int_{}^{}cua sin chia cho cosx nhan voi can bac hai cua (sinx ^2+1)?mong cac ban noi phuong phap truoc nha co the ko can giai >> RAT MONG DUOC CAC BAN CHIA SE NHUNG CACH LAM BAI THU VJ ?> THANKIU NHIEU NA!!!!!!!!1:KHI(69):