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targetq


kimxakiem2507:
[TEX]HD\ :[/TEX]
[TEX]\left{sin(x-\frac{\pi}{4})=\frac{1}{\sqrt2}(sinx-cosx)\\sin2x=(sinx+cosx)^2-1[/TEX][TEX]\Rightarrow{Dat\ \ t=sinx+cosx[/TEX]
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