Q
quanchuon31


lam ho hai con nay nha! minh lam mai khong them ra
(1)
e^2
∫(lnx)^1/2.dx
1
(2)
п/2
∫[{ ( (sinx)^3 – sinx)^1/3}.Cotx.dx]/sinx
п/3
(1)
e^2
∫(lnx)^1/2.dx
1
(2)
п/2
∫[{ ( (sinx)^3 – sinx)^1/3}.Cotx.dx]/sinx
п/3