huong dan lam nhe

S

sonsac99

ui biet lam roy moi nguoi oi'hjhjhjh

http://diendan.hocmai.vn/latex.php?\int\frac{xe^x}{(x+1)^2}dx
dat[TEX]u=xe^x \\suyra\\ du=(e^x+xe^x)dx[/TEX]
[TEX]dv=\frac{1}{(x+1)^2}dx \\suyra\\v=\frac{-1}{x+1}[/TEX]
[TEX]I=\frac{-xe^x}{x+1}+\int\frac{e^x(x+1)}{x+1}dx[/TEX]
[TEX]I=\frac{-xe^x}{x+1}+e^x[/TEX]

nhu vay thay can vao thi xong ak;;;hjhjhj'ngu wa ak


ket qua I=0,5e-1
 
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