

giải các hệ pt sau
[tex]\left\{\begin{matrix} y^{3}=x^{3}(9-x^{3}) \\ x^{2}y+y^{2}=6x \end{matrix}\right.[/tex]
[tex]\left\{\begin{matrix} x^{3}(2+3y)=1 \\ 2x=y^{3}+3 \end{matrix}\right.[/tex]
[tex]\left\{\begin{matrix} y^{3}=x^{3}(9-x^{3}) \\ x^{2}y+y^{2}=6x \end{matrix}\right.[/tex]
[tex]\left\{\begin{matrix} x^{3}(2+3y)=1 \\ 2x=y^{3}+3 \end{matrix}\right.[/tex]