hpt hay

H

hoanghondo94

[tex]\{x^2.y^2-2x+y^2=0 \\2x^3+3x^2+6y-12x+13=0 [/tex]

Chào em , em thử như thế này xem nhé :p

[TEX]pt(1) \ \Rightarrow \ y^2=\frac{2x}{x^2+1}[/TEX][TEX]\Rightarrow x \geq 0 \ ;\ -1 \leq y \leq 1[/TEX]

[TEX]pt(2) \Rightarrow \ y=\frac{-2x^3-3x^2+12x-13}{6}=\frac{(-2x-7){(x-1)}^2}{6}-1[/TEX]

Do [TEX]x \geq 0--->y\leq -1[/TEX]

[TEX]\Rightarrow y=-1 \Rightarrow x =...[/TEX]
;);)
 
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