hoa hoc cuc hay

N

namnguyen_94

Ta có: nNaCL = 0,6 mol ; nH2 = 0,75 mol
[TEX]2 NaCl +2 H_2O ----> 2 NaOH + Cl_2 + H_2 [/TEX]
0,6---------0,6-------0,3-------0,3
[TEX]H_2O ---> H_2 + 1/2 O_2[/TEX]
0,45----0,45----0,225
--> m(dd) = 250 gam
--> C% mNaOH = [tex]\frac{0,6.40.100%}{250}[/tex] = 9,6%
 
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