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pinkylun

$Fe+2HCl--->FeCl_2+H_2$

$n_{Fe}=\dfrac{11,2}{56}=0,2mol$

$=>n_{H_2}=0,2mol$

$=>V_{H_2}=0,2.22,4=4,48l$

$=>n_{HCl}=2.0,2=0,4mol$

$=>V_{d d_{HCl}}=\dfrac{n}{C_M}=\dfrac{0,4}{2}=0,2l=200ml$
 
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