[Hoá 12] Hữu cơ

D

dhbk2013

Gợi ý :
$ClNH_3CH_2COOH + NaOH dư -> NH_2CH_2COOH + NaCl +H_2O$
Vì NaOH dư : nên sẽ có thêm pứ :
$NH_2CH_2COOH + NaOH -----> NH_2CH_2COONa + H_2O$


$NH_2CH_2COONa + HCl dư -> NH_2CH_2COOH + NaCl$
Do HCl (dư) nên :
$NH_2CH_2COOH + HCl -----> ClNH_3CH_2COOH$
 
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