Toán 6 hình lớp 6 nâng cao

Hoàng Long AZ

Cựu Mod Vật lí
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17 Tháng mười hai 2017
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2.2
[tex]\widehat{E1}+\widehat{E2}=180<=>\widehat{E2}+\frac{2}{3}\widehat{E2}=180=>\widehat{E2}=108^{\circ}[/tex]
[tex]\widehat{E2}=\widehat{F2}=108^{\circ}[/tex] (so le trong)
[tex]\widehat{F1}=180^{\circ}-\widehat{F2}=72^{\circ}[/tex]
2.3
[tex]\widehat{E1}+\widehat{E2}=180^{\circ}[/tex]
=> [tex]\widehat{F1}=310^{\circ}-180^{\circ}=130^{\circ}[/tex]
=> [tex]\widehat{F2}=180^{\circ}-\widehat{F1}=50^{\circ}[/tex]
[tex]\widehat{E2}=\widehat{F2}=50^{\circ}[/tex] (so le trong)
[tex]\widehat{E1}=\widehat{F1}=130^{\circ}[/tex] (so le trong)
2.4
[tex]\widehat{ACD}=180^{\circ}-30^{\circ}=150^{\circ}[/tex] (kề bù)
trong tam giác BAC: [tex]\widehat{BAC}=180^{\circ}-30^{\circ}-75^{\circ}=75^{\circ}[/tex]
=> [tex]\widehat{ACM}=\widehat{BAC}=75^{\circ}[/tex](so le trong)
Ta thấy: [tex]\widehat{ACM}=\frac{1}{2}\widehat{ACD}[/tex]
=> CM là phân giác
 
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