[hình học 10] - Tìm Max

C

conga222222

$\eqalign{
& luon\;co:\;MA + AB \ge MB \leftrightarrow AB \ge MB - MA\;\left( 1 \right) \cr
& tuong\;tu\;MA - MB \le {\rm{AB}}\;\left( 2 \right) \cr
& \to \left| {MB - MA} \right| \le AB \cr
& \to \max \;khi\;dau\; = \;xay\;ra\;hay\;M\;la\;giao\;cua\;AB\;va\;\left( d \right) \cr} $
 
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