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Từ (2) [TEX]\Rightarrow \left{ \sqrt{y+1} \le 1 \Rightarrow y \le 0 \\ \sqrt{1-x} \le 1 \Rightarrow x \ge 0 [/TEX]
[TEX]\Rightarrow x.y \le 0 \le \sqrt{x+1} [/TEX]
Dấu "=" [TEX]\Leftrightarrow \left{ xy = 0 \\ \sqrt{1+x} = 0 \right. \Rightarrow \left{ x= - 1 \\ y = 0 [/TEX]
Thế vào (2) không thỏa.
KL: Hệ vô nghiệm