K
kimchung94


giải hệ pt
1/x^3+7y=(x+y)^2+(x^2)y+7x+4
3x^2+Y^2+8y+4+8x
2/(x^2).(y+1)=6y-2
x^4.y^2+2x^2.y^2+y(x^2+1)=12y^2
1/x^3+7y=(x+y)^2+(x^2)y+7x+4
3x^2+Y^2+8y+4+8x
2/(x^2).(y+1)=6y-2
x^4.y^2+2x^2.y^2+y(x^2+1)=12y^2