[tex]\left\{ \begin{array}{l} x^2y^2-2x+y^2 = 0 \\ 2x^2+3 = 4x-y^3 \end{array} \right.[/tex]\Leftrightarrow[tex]\left\{ \begin{array}{l} y^2 = \frac{2x}{x^2+1} \\ y^3 =-2x^2+4x-3 \end{array} \right.[/tex]
*[TEX]y^2[/TEX]=[TEX]\frac{2x}{x^2+1}[/TEX] \Rightarrow x\geq0 \Rightarrow[TEX]x^2+1[/TEX]\geq2x
\Rightarrow[TEX]y^2[/TEX]\leq1\Rightarrow -1\leqy\leq1
*[TEX]y^3=-2x^2+4x-3[/TEX] \leq-1\Rightarrow y\leq-1
suy ra được y=-1 ; x=1