he pt giup a voi

B

buimaihuong

[TEX]\left{\begin{x -y= 2y^2 + 1}\\{2\sqrt{x +y} + 2\sqrt{x-2y}=3y} [/TEX]

đặt [TEX]\left{\begin{\sqrt{x +y} = a}\\{\sqrt{x-2y} = b} [/TEX]

\Rightarrow [TEX]\left{\begin{x +y = a^2}\\{x-2y = b^2} [/TEX]

\Rightarrow [TEX]a^2 - b^2 = 3y[/TEX]

vậy ta có pt1: [TEX]2a + 2b = a^2 - b^2[/TEX]

\Rightarrow [TEX]a - b = 2 [/TEX](th a + b khác 0)
 
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