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vipboycodon

$Pt 2 \leftrightarrow x-y-1+\sqrt{\dfrac{2(x+y)}{x+3y+1}}-1 = 0$
$\leftrightarrow x-y+1+\dfrac{\dfrac{2(x+y)}{x+3y+1}-1}{\sqrt{\dfrac{2(x+y)}{x+3y+1}}+1} = 0$
$\leftrightarrow (x-y-1)(1+\dfrac{1}{\sqrt{\dfrac{2(x+y)}{x+3y+1}}+1}) = 0$
$\leftrightarrow x-y-1 = 0$
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