hang so can bang

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pt:............................2SO2 + O2 ---> 2SO3
ban đầu.....................0,7.....0,3..........0
Pứ...............................2x<----x--------->2x
sau pứ:....................0,7-2x...0,3-x.........2x
tổng thể tích sau p ứ: V=0,7-2x+0,3-2x+2x=1-x
theo đề bài ---> 2x = 0,5.(1-x) --->x=0,2
--> Kc = (2x)^2/(0,3-x)(0,7-2x)^2 = 17,78
 
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