Ham so lien tuc

B

bugana

Đặt f(x)=ax^2+bx+c
a/2001+b/2000+c/1999=0 <=> 2000/2001.a+b+2000/1999c=0
<=> (2000/2001)^2.a+2000/2001.b+2000^2/(2001.1999).c=0
<=> (2000/2001)^2.a+2000/2001.b+c+ c(2000^2/(2001.1999)-1)=0
=>f(2000/2001)+f(0).(2000^2/(2001.1999)-1)=0
=>f(2000/2001).f(0).(2000^2/(2001.1999)-1)<0
=>f(2000/2001).f(0)<0
=>pt có no thuộc (0;1)
 
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