N
ngocxit9507


GTLN GTNN cua ham so?
1/ CM bdt
$ ax^4 + bx^3 + 1 \geq 0 $ thoa man voi moi x khi $256a^3 \geq 27b^4$
2/ m=? de pt sau co nghjem
$x^2 + ( m + 2 )x + 4 = ( m - 1 ) \sqrt{ x^3 + 4x} $
3/ cho cac so thuc a,b,c khong âm thỏa mãn a + b + c = 1 tim MIN cua bt
$P= 3(a^2b^2 + b^2c^2 + c^2a^2 ) + 3( ab + bc + ca ) +2\sqrt{a^2 + b^2 + c^2}$
1/ CM bdt
$ ax^4 + bx^3 + 1 \geq 0 $ thoa man voi moi x khi $256a^3 \geq 27b^4$
2/ m=? de pt sau co nghjem
$x^2 + ( m + 2 )x + 4 = ( m - 1 ) \sqrt{ x^3 + 4x} $
3/ cho cac so thuc a,b,c khong âm thỏa mãn a + b + c = 1 tim MIN cua bt
$P= 3(a^2b^2 + b^2c^2 + c^2a^2 ) + 3( ab + bc + ca ) +2\sqrt{a^2 + b^2 + c^2}$
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