giup voi

C

chonhoi110

Đề là $\dfrac{x+1}{x+1}.\dfrac{x+2}{x+1}=12$ hả bạn :D

Ta có: $\dfrac{x+1}{x+1}.\dfrac{x+2}{x+1}=12$

$\leftrightarrow \dfrac{x+2}{x+1}=1$

$\rightarrow x+2=12x+12$

$\leftrightarrow -11x=10$

$\leftrightarrow x=\dfrac{-10}{11}$
 
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