giúp với

C

cfnguyen84

tìm min

Y=tan ^2(x-pi/3 )+ tan ^2 (x+pi/3 )

y=sin^2(x-pi.3)sin^2(x+pi/3)/(cos^2(x-pi/3)cos^2(x+pi/3)
=((1/2sinx-can3/2cosx)(1/2sinx+can3/2cosx))^2/((1/2cosx-can3/2sinx)(1/2cosx+can3/2sinx))^2
=(1/4sin^2x-3/4cos^2x)^2/(1/4cos^2x-3/4sin^2x)^2
=(sin^2x-3cos^2x)^2/(cos^2x-3sin^2x)^2
Để y nho nhat thi sin^2x-3cos^2x nhỏ nhất=>1-4cos^2x=o
<=>cosx=1/2=>y=okhix=+-pi/3+k2pi
 
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