kho qua gam mai ko ra**********************************************************************dd
ta có [tex]{log}_{2}24 - \frac{1}{2}{log}_{2}72 = {log}_{2}3 + {log}_{2}8 - \frac{1}{2}\left({log}_{2}9+{log}_{2}8 \right) = {log}_{2}3+3-{log}_{2}3-\frac{3}{2} = \frac{3}{2}[/tex]
và [tex]{log}_{3}18 - \frac{1}{3}{log}_{2}72 = {log}_{3}2 + {log}_{3}9 - \frac{1}{3}\left({log}_{3}9+{log}_{3}8 \right) = {log}_{3}2 +2 - \frac{2}{3}-{log}_{3}2 = 2-\frac{2}{3} = \frac{4}{3}[/tex]
vậy đáp án là [tex] \frac{9}{8}[/tex]