giup to lam bai nay vơi

B

braga

Đề sai !! :D

[TEX]A=\frac{1}{2^3} +\frac{1}{3^3} +....+\frac{1}{n^3}[/TEX]

[TEX]A>\frac{1}{2.3.4}+\frac{1}{3.4.5}+...............+\frac{1}{(n-1)n(n+1)}[/TEX]

[TEX]A>\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+....................+\frac{1}{(n-1)n}-\frac{1}{n(n+1)}[/TEX]

[TEX]A>\frac{1}{6}-\frac{1}{n(n+1)}. \ \text{Voi} \ n\geq 2 \ \text{Thi} \ A>\frac{1}{4}!!![/TEX]
 
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T

trungvodoi024

ban oi nham dau rui dau < co ma

Đề sai !! :D

[TEX]A=\frac{1}{2^3} +\frac{1}{3^3} +....+\frac{1}{n^3}[/TEX]

[TEX]A<\frac{1}{2.3.4}+\frac{1}{3.4.5}+...............+\frac{1}{(n-1)n(n+1)}[/TEX]

[TEX]A<\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+....................+\frac{1}{(n-1)n}-\frac{1}{n(n+1)}[/TEX]

[TEX]A<\frac{1}{6}-\frac{1}{n(n+1)}. \ \text{Voi} \ n\geq 2 \ \text{Thi} \ A<\frac{1}{4}!!![/TEX]
sãi dau rui ban oi ::p
sau day viet cho no dai!
hoc van la vinh cuu
ban xet nham dau
haha
 
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