giup mình với

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niemkieuloveahbu

[TEX]\blue \text{\int^{\frac{\pi}{2}}_0|sin^4x-cos^4x|dx=\int^{\frac{\pi}{2}}_0|-cos2x|dx=\int^{\frac{\pi}{4}}_0cos2xdx-\int^{\frac{\pi}{2}}_{\frac{\pi}{4}}cos2xdx=\frac{1}{2}sin2x|^{\frac{\pi}{4}}_0-\frac{1}{2}sin2x|^{\frac{\pi}{2}}_{\frac{\pi}{4}}}[/TEX]
 
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