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dien0709

Vẽ hình thoi ADCB=>h=d(SA;BC)=d(C;(SAD))[TEX]=\frac{3V_{S.ADC}}{S_{SAD}}[/TEX]

+[TEX]SA=SD=a\sqrt[]{2}=>S_{SAD}=\frac{a^2\sqrt[]{7}}{4} [/TEX]

+ [TEX] V_{S.ADC}=\frac{a^3\sqrt[]{3}}{12}=>h=\frac{a\sqrt[]{21}}{21}[/TEX]
 
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