giúp mình nguyên hàm với

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nguyenbahiep1

[laTEX]I = \intdx - 2 \int \frac{dx}{sin x +2} \\ \\ I = x -\int \frac{(1+tan^2(\frac{x}{2}))dx}{tan^2(\frac{x}{2}) +tan(\frac{x}{2})+1} \\ \\ I = x - I_1 \\ \\ u = tan(\frac{x}{2}) \Rightarrow du = \frac{1}{2}(1+tan^2(\frac{x}{2}))dx \\ \\ I_1 = \int\frac{2du}{u^2+u+1} \\ \\ u = \frac{\sqrt{3}}{2}tant[/laTEX]
 
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